60 lines
3.2 KiB
Python
60 lines
3.2 KiB
Python
from langchain.text_splitter import CharacterTextSplitter
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import re
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from typing import List
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class ChineseTextSplitter(CharacterTextSplitter):
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def __init__(self, pdf: bool = False, sentence_size: int = 250, **kwargs):
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super().__init__(**kwargs)
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self.pdf = pdf
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self.sentence_size = sentence_size
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def split_text1(self, text: str) -> List[str]:
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if self.pdf:
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text = re.sub(r"\n{3,}", "\n", text)
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text = re.sub('\s', ' ', text)
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text = text.replace("\n\n", "")
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sent_sep_pattern = re.compile('([﹒﹔﹖﹗．。！？]["’”」』]{0,2}|(?=["‘“「『]{1,2}|$))') # del ：；
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sent_list = []
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for ele in sent_sep_pattern.split(text):
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if sent_sep_pattern.match(ele) and sent_list:
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sent_list[-1] += ele
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elif ele:
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sent_list.append(ele)
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return sent_list
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def split_text(self, text: str) -> List[str]: ##此处需要进一步优化逻辑
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if self.pdf:
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text = re.sub(r"\n{3,}", r"\n", text)
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text = re.sub('\s', " ", text)
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text = re.sub("\n\n", "", text)
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text = re.sub(r'([;；.!?。！？\?])([^”’])', r"\1\n\2", text) # 单字符断句符
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text = re.sub(r'(\.{6})([^"’”」』])', r"\1\n\2", text) # 英文省略号
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text = re.sub(r'(\…{2})([^"’”」』])', r"\1\n\2", text) # 中文省略号
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text = re.sub(r'([;；!?。！？\?]["’”」』]{0,2})([^;；!?，。！？\?])', r'\1\n\2', text)
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# 如果双引号前有终止符，那么双引号才是句子的终点，把分句符\n放到双引号后，注意前面的几句都小心保留了双引号
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text = text.rstrip() # 段尾如果有多余的\n就去掉它
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# 很多规则中会考虑分号;，但是这里我把它忽略不计，破折号、英文双引号等同样忽略，需要的再做些简单调整即可。
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ls = [i for i in text.split("\n") if i]
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for ele in ls:
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if len(ele) > self.sentence_size:
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ele1 = re.sub(r'([,，.]["’”」』]{0,2})([^,，.])', r'\1\n\2', ele)
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ele1_ls = ele1.split("\n")
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for ele_ele1 in ele1_ls:
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if len(ele_ele1) > self.sentence_size:
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ele_ele2 = re.sub(r'([\n]{1,}| {2,}["’”」』]{0,2})([^\s])', r'\1\n\2', ele_ele1)
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ele2_ls = ele_ele2.split("\n")
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for ele_ele2 in ele2_ls:
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if len(ele_ele2) > self.sentence_size:
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ele_ele3 = re.sub('( ["’”」』]{0,2})([^ ])', r'\1\n\2', ele_ele2)
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ele2_id = ele2_ls.index(ele_ele2)
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ele2_ls = ele2_ls[:ele2_id] + [i for i in ele_ele3.split("\n") if i] + ele2_ls[
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ele2_id + 1:]
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ele_id = ele1_ls.index(ele_ele1)
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ele1_ls = ele1_ls[:ele_id] + [i for i in ele2_ls if i] + ele1_ls[ele_id + 1:]
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id = ls.index(ele)
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ls = ls[:id] + [i for i in ele1_ls if i] + ls[id + 1:]
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return ls
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